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  • Blinkster182
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Post July 27th, 2004, 2:13 pm

When I first started my site I knew that it would be hard. But this is the hardest bit. My person logs on and on all my pages there Username is shown. But the thing is, if they go onto the main page without being logged on they get this error:
Quote:
Warning: Undefined variable: username in c:\program files\apache group\apache\htdocs\frimps\menu.inc

The only way I can think of doing the page without getting that error is if at the start of the page I set the variable Username to nothing but that logs the person out.

[fade]Please help me. Im confused[/fade]
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Post July 27th, 2004, 2:13 pm

  • this213
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Post July 28th, 2004, 5:15 am

do a test to see if your user is logged in and if so set $username accordingly, if not assign $username a name such as "Guest"


$this
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  • Blinkster182
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Post July 29th, 2004, 3:05 am

So I check to see if the other session variable which Ive called $auth is set to TRUE and if it isnt then set the varialbe $username to "guest"? :?:
  • this213
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Post July 29th, 2004, 3:11 am

Why not pass the user's username to the variable? Then you can do things like say "Hi George!" on the page when a user is logged in.

If $auth = TRUE means a user is logged in, you could also do as you stated.
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Post July 29th, 2004, 7:17 am

I do something like this in my header:

Code: [ Select ]
<? if (!empty($SESSION["username"])) {
    echo("<a href='index.php' class='whitelink'>home</a> | ");
    echo("<a href='logout.php' class='whitelink'>log out</a> [ ".$SESSION["username"]." ]");
 }
?>
  1. <? if (!empty($SESSION["username"])) {
  2.     echo("<a href='index.php' class='whitelink'>home</a> | ");
  3.     echo("<a href='logout.php' class='whitelink'>log out</a> [ ".$SESSION["username"]." ]");
  4.  }
  5. ?>


Basically, if username (which i store in the session) isn't empy, I show it and give them the logout option.

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