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Programming Challenge: Rock, Paper, Scissors

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Post December 3rd, 2010, 4:17 pm

This might be a dud but I'm wondering how many ways can you write a function to tell you the outcome of who would win in a game of Rock Paper, Scissors.

Argument choose is yours, the function just has to return some sort of answer that would tell you who won the game, aka player 1 or player 2 or a draw.

* The function must take two player inputs in some fashion and return who won.

And no, Rock can't bust through paper ;)

I have a solution that I'll post at a later date (Its quite a *simple* solution). Come up with as many ways as you can, any language can be submitted, once a solution has been posted, try to solve it in a different way.

If your not familiar with the game: http://en.wikipedia.org/wiki/Rock-paper-scissors
#define NULL (::rand() % 2)
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Post December 3rd, 2010, 4:17 pm

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Post December 3rd, 2010, 4:59 pm

PHP Code: [ Select ]
<?php
$solutions = array('1' => 'Player 1', '2' => 'Player 2', '3' => 'Draw');
$id = rand('1','3');
echo $solutions[$id];
?>
  1. <?php
  2. $solutions = array('1' => 'Player 1', '2' => 'Player 2', '3' => 'Draw');
  3. $id = rand('1','3');
  4. echo $solutions[$id];
  5. ?>
There you go :D Took me 5 seconds.
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Post December 3rd, 2010, 5:47 pm

Maybe I should clarify it actually has to take two player inputs as arguments and return the winner.

Whether you pass those values by reference in an array, class, struct or anything else is up to you. Besides Bogey, that's not a function :P
#define NULL (::rand() % 2)
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Post December 3rd, 2010, 9:43 pm

Fine, here is something I've created that took me 2 minutes :lol:
PHP Code: [ Select ]
<?php
function ropasci($pl1, $pl2)
{
    if($pl1 == 'rock' && $pl2 == 'paper')
    {
        return 'Player 2 wins: paper over rock';
    }
    elseif($pl1 == 'rock' && $pl2 == 'scissors')
    {
        return 'Player 1 wins: Rock over scissors';
    }
    elseif($pl1 == 'paper' && $pl2 == 'rock')
    {
        return 'Player 1 wins: paper over rock';
    }
    elseif($pl1 == 'paper' && $pl2 == 'scissors')
    {
        return 'Player 2 wins: Scissors over paper';
    }
    elseif($pl1 == 'scissors' && $pl2 == 'rock')
    {
        return 'Player 2 wins: Rock over scissors';
    }
    elseif($pl1 == 'scissors' && $pl2 == 'paper')
    {
        return 'Player 1 wins: Scissors over paper';
    }
    elseif($pl1 == $pl2)
    {
        return "Draw: $pl1 equals $pl2";
    }
    else
    {
        return false;
    }
}
?>
  1. <?php
  2. function ropasci($pl1, $pl2)
  3. {
  4.     if($pl1 == 'rock' && $pl2 == 'paper')
  5.     {
  6.         return 'Player 2 wins: paper over rock';
  7.     }
  8.     elseif($pl1 == 'rock' && $pl2 == 'scissors')
  9.     {
  10.         return 'Player 1 wins: Rock over scissors';
  11.     }
  12.     elseif($pl1 == 'paper' && $pl2 == 'rock')
  13.     {
  14.         return 'Player 1 wins: paper over rock';
  15.     }
  16.     elseif($pl1 == 'paper' && $pl2 == 'scissors')
  17.     {
  18.         return 'Player 2 wins: Scissors over paper';
  19.     }
  20.     elseif($pl1 == 'scissors' && $pl2 == 'rock')
  21.     {
  22.         return 'Player 2 wins: Rock over scissors';
  23.     }
  24.     elseif($pl1 == 'scissors' && $pl2 == 'paper')
  25.     {
  26.         return 'Player 1 wins: Scissors over paper';
  27.     }
  28.     elseif($pl1 == $pl2)
  29.     {
  30.         return "Draw: $pl1 equals $pl2";
  31.     }
  32.     else
  33.     {
  34.         return false;
  35.     }
  36. }
  37. ?>
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Post December 5th, 2010, 2:10 pm

HASKELL Code: [ Select ]
winner :: String -> String -> String
winner p1 p2
  | p1c - p2c == 1 || p1c - p2c == -2 = p1
  | p1c == p2c = "Tie"
  | otherwise p2
  where
    p1c = rand 2
    p2c = rand 2
  1. winner :: String -> String -> String
  2. winner p1 p2
  3.   | p1c - p2c == 1 || p1c - p2c == -2 = p1
  4.   | p1c == p2c = "Tie"
  5.   | otherwise p2
  6.   where
  7.     p1c = rand 2
  8.     p2c = rand 2
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Post December 6th, 2010, 10:28 am

This is what I came up with after a while

Code: [ Select ]
function name(p1,p2) {
  return (3+p1-p2) % 3;
}
  1. function name(p1,p2) {
  2.   return (3+p1-p2) % 3;
  3. }


Returns '1' - Player one has won.
Returns '2' - Player two has won.
Returns '3' - Tie between players.

Where p1, p2 are:
0 - Rock
1 - Paper
2 - Scissors
#define NULL (::rand() % 2)
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Post December 6th, 2010, 11:30 am

Oh, I read the question completely wrong. I took two player names and generated random values for the "throws". :lol:
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Post December 6th, 2010, 4:35 pm

That's pretty slick Spoof. :D I gave it a whirl with bitwise operators, but didn't get anywhere with them.
Strong with this one, the sudo is.

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