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$this keyword as an argument?

  • RockmanTV
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Post April 28th, 2010, 9:49 am

I'm working on building up my library of classes and I'm writing a class that manages a site's hyperlinks. In this class I have a writeLink function that has an optional second argument to change how the link uses it's quotes for attributes. As you can see by default, the object sets the quotes to 'double'. I want to give the user of the class the authority to temporarily override this setting for individual writeLink calls.

I thought this could be performed by setting the $qt argument to $this->quotes which would then only be overridden if a user specifies otherwise. This doesn't seem to be the case however as I get a "Parse error: syntax error, unexpected T_VARIABLE" whenever I user the $this keyword for the argument. Any ideas?


Code: [ Select ]
private $quotes = 'double';

function writeLink($markup,$qt=$this->quotes){

}
  1. private $quotes = 'double';
  3. function writeLink($markup,$qt=$this->quotes){
  5. }
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Post April 28th, 2010, 9:49 am

  • joebert
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Post April 28th, 2010, 10:00 am

PHP Code: [ Select ]
function writeLink($markup, $qt = null)
{
    if(empty($qt)) $qt = $this->quotes;
}
  1. function writeLink($markup, $qt = null)
  2. {
  3.     if(empty($qt)) $qt = $this->quotes;
  4. }
Strong with this one, the sudo is.
  • RockmanTV
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Post April 28th, 2010, 10:16 am

There's no way to do that in the methods' arguments?

I'm trying to make my script as compact as possible :) But I'm thinking you're right and I'll end up having to perform an if statement to check instead.
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Post April 28th, 2010, 11:40 am

Looks like you're limited to strings, arrays, and null, for default values.


There's a somewhat confusing note at the bottom of the manual page.

Quote:
Note: As of PHP 5, default values may be passed by reference.


I think that just means you can do something like this though.

PHP Code: [ Select ]
function f(&$var = 'f')
Strong with this one, the sudo is.

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