First of all, what system type is this? Linux I presume; which distribution?
Second, that does not look like a valid cron time, here's a part of 'man 5 crontab';
field allowed values
----- --------------
minute 0-59
hour 0-23
day of month 1-31
month 1-12 (or names, see below)
day of week 0-7 (0 or 7 is Sun, or use names)
- field allowed values
- ----- --------------
- minute 0-59
- hour 0-23
- day of month 1-31
- month 1-12 (or names, see below)
- day of week 0-7 (0 or 7 is Sun, or use names)
What times are you trying to run it?
I have no idea how those panels work but it looks as though it is trying to set up the entire line as the shell command to be executed. In other words, it is seeing the first 0 as a shell command instead of part of the crontab entry. First thing, figure out how to enter a crontab entry.
Then figure out a proper crontab entry.
Then create a properly designed command syntax; This one makes no sense to me.
I would instead, create a shell command that has all that information in it. This way you could modify it at will, without entering in a new crontab entry.
Say, maint.sh; which contains:
wget -q http://www.server.com/phpAdsNew/maintenance/maintenance.php
Then using a syntactically correct crontab, call it thusly (say run five min after midnight every day);
5 0 * * * /home/bin/maint.sh >/dev/null 2>&1
Then, as previously mentioned, you may edit maint.sh at whim.
The one thing about your command syntax -- and why mine did not match yours -- which confused me would have been the request for -q (quiet, no output) with the -O (for direct output to a file, which was never designated anyway) followed by a stray '-'. I would say, run 'man wget' from the command window if possible to understand the command syntax. If you want output sent to a file, don't quiesce the output with a -q.
If you do not have command line access to a linux/unix machine, I am sure it is available on the net someplace; I can also post it as it's not all that long.
Cheers.